[Free] 2018(Jan) EnsurePass Pass4sure Juniper JN0-360 Dumps with VCE and PDF 71-80

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2018 Jan Juniper Official New Released JN0-360
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Juniper Networks Certified Internet Specialist, – Service Provider (JNCIS-SP)

Question No: 71

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An operator is unable to establish any IS-IS adjacencies on a router in the network. Based on the configuration shown in the exhibit, what is the problem?

  1. Interface loO must be configured in the IS-IS hierarchy

  2. Each network interface needs a unique family ISO address

  3. The IS-IS level for an each interface must be specified

  4. The ISO address for interface loO is not in hex format

Answer: A

Question No: 72

What are three IS-IS PDU types? (Choose three.)

  1. type length value

  2. link-state

  3. partial sequence number

  4. database description

  5. complete sequence number

Answer: B,C,E

Question No: 73

What are two valid statements for virtual switches on MX Series devices? (Choose two.)

  1. Integrating routing and bridging (IRB) interfaces are supported.

  2. Layer 2 interfaces are supported.

  3. Interfaces are inherently loop free.

  4. Trunk interfaces are not supported.

Answer: A,B

Question No: 74

Your area border router (ABR) receives type 1.2 and 5 link-state advertisements (LSAs) from a non-backbone area.

What would the ABR do with the information learned from the non-backbone area?

  1. The ABR will generate type 2 and 3 LSAs and flood type 5 LSAs to the backbone area

  2. The ABR will generate only type 3 LSAs and flood only type 5 LSAs to the backbone area

  3. The ABR will generate type 3 and 4 LSAs. And flood type 5 LSAs to the backbone area

  4. The ABR will generate only type 4 LSAs and flood only type 5 LSAs to the backbone area

Answer: C

Question No: 75

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In the exhibit, how many full OSPF adjacencies will R3 have?

  1. 0

  2. 1

  3. 2

  4. 3

Answer: C

Question No: 76

What are two characteristics of a traditional Ethernet LAN? (Choose two.)

  1. Nodes share a physical medium.

  2. Nodes can successfully transmit simultaneously.

  3. It consists of a single broadcast domain.

  4. Nodes use a step-up algorithm when collisions are detected.

Answer: A,C

Question No: 77

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In the exhibit, all routers are sending routes to Router B. Which routes will be advertised from Router B to Router E?

  1. BGP routes learned from Router A only

  2. BGP routes learned from Router D only

  3. BGP routes learned from Routers A and C only

  4. BGP routes learned from Routers A, C, and D only

Answer: D

Question No: 78

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Based on the configuration shown in the exhibit, what will be the state of the IS-IS levels on interface ge-0/0/0.100?

  1. Level 1 is enabled and Level 2 is disabled.

  2. Level 1 is disabled and Level 2 is enabled.

  3. Level 1 is enabled and Level 2 is enabled.

  4. Level 1 is disabled and Level 2 is disabled.

Answer: D

Question No: 79

– Exhibit –

user@routergt; show route 0/0 exact detail

inet.0: 14 destinations, 14 routes (14 active, 0 holddown, 0 hidden)

0.0.0.0/0 (1 entry, 1 announced)

*Aggregate PreferencE. 130

Next hop typE. Router, Next hop index: Next-hop reference count: 4

Next hop: 172.30.25.1 via ge-0/0/1.100, selected StatE.

Local AS: 65400

AgE. 1:03:46

Task: Aggregate

Announcement bits (2): 0-KRT 2-OSPF AS path: I

Flags: Generate Depth: 0 Active Contributing Routes (1): 10.0.0.0/16 proto BGP

– Exhibit –

Click the Exhibit button.

You are advertising the route in the exhibit to your OSPF neighbors. What happens if the 10.0.0.0/16 route is unavailable?

  1. The default route will remain active and will quot;blackholequot; all traffic from your OSPF peers.

  2. The default route will become unavailable and will no longer be advertised to your OSPF peers.

  3. The default route will remain active and will continue to be advertised to your OSPF peers.

  4. The default route will become unavailable and will continue to be advertised to your

OSPF peers.

Answer: B

Question No: 80

In Q-in-Q tunneling, what is the purpose of the pop-swap operation?

  1. pop the outer tag and swap the inner tag

  2. pop and swap the inner tag

  3. pop and swap both outer and inner tags

  4. pop the inner tag and swap the outer tag

Answer: A

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